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0.0001x^2+0.36x+1=0
a = 0.0001; b = 0.36; c = +1;
Δ = b2-4ac
Δ = 0.362-4·0.0001·1
Δ = 0.1292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.36)-\sqrt{0.1292}}{2*0.0001}=\frac{-0.36-\sqrt{0.1292}}{0.0002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.36)+\sqrt{0.1292}}{2*0.0001}=\frac{-0.36+\sqrt{0.1292}}{0.0002} $
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